MICROELECTRONIC CIRCUIT DESIGN
THIRD EDITION
by
RICHARD C. JAEGER and TRAVIS N. BLALOCK
Third Edition Errata - Updated 6/1/08
Text Corrections
Page 33 The first answer to the exercise at the
bottom of the page should be 9.20 kohms.
Page 46 The units on the vertical axis of Fig. 2.4
should be cm-3.
Page 108 Exercise: 2.13 mA, 1.13 mA, -1.27 V
Page 117 Exercise: 0.912 ms,
19.7o
Page 118 Exercise at bottom:
0.994 V, 1.07 V
Page
169 The first
line of Table 4.2: The parameters
for Our Text should be K'n or K'p.
Page
172 Units in the
equation near the bottom of the page should be A/V2
Page
178 Third
exercise (25.4 uA, 6.52 V)
Page
182 Exercise
answer should be 83.2 uA
Page
186 Exercise
(2.22 uA, 2.96 mV)
Page
192 Last
exercise 127 GHz
Page
193 Near the end
of the first sentence: 105 V/cm
Page
217 Last answer
in exercise - 1.07 mA
Page
223 Exercise
answers (b) 0.300 fA, 5.26 aA, -0.305 fA
Page
229 VCE
in second exercise should be 5.44 V
Page
237 The units on
Dn in the exercise are cm2/s.
Page
240 First exercise
- 1.24 uF
Page
250 Q-Point:
(206 uA, 4.18 V)
Page
278 Fig.
6.3(a): Remove the labels and
arrows indicating NML and NMH.
Page
281 Center of
Fig. 6.5: Left-hand tPLH should be tPHL
Page
302
Exercise; IDD =
278 uA
Page
305 Given Data
in Ex. 6.7: 0.20 mW
Page
306 In the
figure, the voltages should be VDSS = 0.20 V VDSL =
3.10 V
Page
321 Spice
Results Table: 11000
132 64.4 0 | 11100
64.6 31.9 31.9
Page
330
Exercise: 4.47 ns -->
4.97 ns, 3.84 ns --> 2.84 ns
Page
358
Exercise: 1.27 V
Page
362 C = 0.75 pF
in the first exercise. TauP
= 2.4 x (2pF/0.75pF) x (2/1)/(8/1) = 1.6 ns Also "delay of 1.6 ns" just above the
equation. The delay in Fig.
7.13(b) is also 1.6 ns.
Page
362 In the
second exercise: (W/L)P
= 78.8/1 (W/L)N =
31.5
Page
380 Execise: P =
12.5 mW
Page
403 Second
exercise: The substrates of the
PMOS devices must also be connected to VDD.
Page
411 Exercise:
Fall time = 1.30 ns.
Page
420 Exercise: P
= 1.0 mW.
Page
424 Exercise:
3.00 V (3.66 V corresponds
to an input of 5 V in Fig. 8.35(b).)
Page
454 Exercise: -VEE
= -5.2 V
Page
456 The
frequency used in the simulations is 2000 Hz, not 1000 Hz.
Page
461 Exercise
answers 1.66 ns, 6.0 pJ
Page
464 Second line in Section 9.9.2 should refer to Eq. (5.30)
Page
466 First
exercise: 6.00 --> 3.00
Page
469 -5.49 mA
Page
479 What is iL
if Q4 … Answers:
92.3 mA; 9.16 mA; no
Page
512 Fig.
10.5(b): The input signal for this plot is 100 mV as in Fig. 10.4 but biased
at 0.4 V.
Page
519 262 ohms
--> 3.82mS (1/262 ohms)
Page
520 (Av)2(RS+Rin)/RL
Page
531 The
numerator coefficient should be 6 x 106.
Page
533 The
numerator of the transfer function should be multiplied by "s". Answers: 25.8 kHz, 25.7 kHz
Page
549 Example
11.2: The gain of E1 should be
negative, -109. Ignore the first two answers in the
exercise.
Page
559 Third
example: -18.0, 4.50 V, -92.1 uA
Page
573 In the
figure, voltage gain block E1 is upside down, and its negative input should be
connected to the output terminal. Also, Gain = +106.
Page
577 Sensitivity
= 3Q-1 = 1.12
Page
583 Q = 0.471
Page
587 First
exercise: VZ > 15.6
V
Page
594 Tr
= 13.0 us
Page
617 44.2, 36.2,
4.20 (10.5 %), -3.60 (-9.5 %)
Page
624 Middle of
the page: VCM = 5.0
V and CMRR ≥ 3.65 x104
Page
626 Example
12.6: Known information: A = 80 dB
Page
645 Second
denominator: s + 3.16p x 104
Page
647 4190 Hz
Page
656 SPICE
Results: Rin = 28.9 x 1012 ohms
Page
670 Caption to
Fig. 13.1: similar bit larger
-> similar but larger
Page
673 First
Exercise (1.45 mA, 3.57 V)
Page
692 The exercise
is misplaced in the text and should refer to, and follow, Exercise 13.4. -130 should be -159, -222 should be
-176, and 42% should be 10%.
Page
693 Ignore l = 0.0133/V.
Page
697 The second
exercise should refer to capacitor C2, and -145 should be -159.
Page
700 VAF should be 75 V
in the SPICE simulation. Both
exercise should refer to RiC, not Rout. The exercise answers should be RiC
= 4.85 Mohms < 6.28 Mohms. (Rout = 21.9 kohms).
Page
704 40.0 should be
41.5
Page
717 Second
exercise: -12.5 --> -24.4
Page
725 The SPICE value of
the input resistance should be 14.8 kohms, not 16.0 kohms.
Page
726 Exercise:
2220--2150
Page
726 Example 13.10 -
"with feedback bias" should be deleted
Page
734 In the second exercise,
9.5 V should be 4.5 V.
Page
761 Last exercise should
refer to Fig.14.2. Answers: 78.1
kohms, 892 kohms
Page
766 In the equation at the
top of the page, 116 kohms --> 1.16 Mohms twice.
Page
767 Exercise - Largest
values of vi …
0.569 V --> 0.580 V
Page
772 Ini Eq. (14.310, R4
--> R6
Page
778 Second Exercise: 10.4,
5.04; Third exercise: 8.48 <10.4<<176, 4.11<8.48<10.5
Page
796 0.579 uF --> 6.8 uF,
12.2 nf --> 0.12 uF, 6.13 nF --> 0.068 uF; 0.232 uF --> 2.2 uF, 714 pf --> 8200 pF, 6.19 nF
--> 0.068 uF
Page
797 795 --> 820 pF; 0.039
--> 0.042 uF
Page
800 Eq. (14.68): VDD
+ VGS - vs ≥ VGS - VTN or VDD ≥ vgg - VTN = vgg
- 1.5 V
Note that vGS = VGS + vgs = VGS
+ (vgg - vs)
Page
803 The emitter arrow should
point into the transistor in Fig. 14.33.
Page
808 Eq. (14.88), VP
should be VTN.
Page
811 Second exercise JFET
--> FET; Last exercise: -200, -50.0.
Page
820 Last exercise 1840
should be 1150
Page
842 SPICE results: VCE-VBE
= 7.90 V and BF = 116
Page
851 5.20 --> 5.30
Page
858 4.9 Gohm --> 4.8 Gohm
Page
893 9.34 V --> 9.96 V;
200 uA --> 189 uA; 10.6 Mohm --> 10.3 Mohm
Page
903 5.94 Mohm, 1.19 Mohm
Page
906 224 ohm --> 2.24 kohm
Page
915 5th line above check of
results: Kn = 1.25 mS/V.
Page
932 1.25 V --> 1.37 V
Page
938 SPICE Exercise Results:
64.164 uV, 0.520
Page
992 C2 and C3
are reversed in Fig. 16.4(c).
Page
995 At the top of the page,
the results for wZ2 and wZ3 should be interchanged.
Page
996 First exercise "…
if the value of C2 is reduced…"
Page
999 Second exercise answers:
33.6 ms, 1.47 ms, 14.3 ms, 124 Hz
Page
1005 Second exercise answers: 24.4 ms, 1.16 ms, 6.66 Hz, 0.550
Page
1019 Eq. (16.80): Beta1
should be RI
Pages
1021 & 1030 Examples 16.6 and 16.7:
C1 = C2 = 3.9 uF, C3 = 0.082 uF
Page
1023 Second exercise: 445 MHz; ignore the comment. Third exercise: -135, 837 kHz, 525 MHz
Page
1026 Fig. 16.38(b): The current source value is ix and vx
is the voltage across ix.
Page
1031 Second exercise: -29.3, 6.70 MHz, 196 MHz
Page
1033 First exercise: 48.2, 18.7 MHz, 903 MHz
Page
1041 4.20 MHz --> 6.27 MHz; ignore comment.
Page
1041 Eq. (16.152): At end, "phi" should be zero: rp01
Page
1042 22.7 MHz --> 11.6 MHz
Page
1043 Exercise: 159 kHz, 39.8 kHz;
C1 should be 0.01 uF in Fig. 16.52(b).
Page
1145, Eq. (17.142) The "s" term should be s[(C3 + CGD)G +gmCGD]
Page
1050 Second exercise: 29.6 --> 23.9, 6.29 --> 5.07, 296 --> 239
Page
1053 First exercise: 4.59 MHz, 093.3 kHz, 49.2, -80.2. Ignore the comment at end. Second exercise: 4.59 MHz.
Page
1086 First exercise: +39.1 mS.
Second exercise: -252 kohms, -0.01 mS, -71.6 kohms, 605 ohms, 863 ohms.
Page
1110 In the exercise, RI should be RD.
Page
1122 Exercise: 27.6 o --> 69.4o
Page
1127 Exercise should read fT, fZ, and fB
Page
1130 Extraneous "2" in Avt2 expression immediately after RC1
Page
1144 Exercises: 15.9 kHz
Problem Statements
2.48 The second
dimension in Fig. P2.48 should be 2 mm,
not 3 mm
4.39 Page (c)
should refer to Fig. P4.39(b).
4.134 VDS = -5 V
7.91 Use VDD
= 2.5V
8.23 CBL
= 500 fF
11.10 & 11.18 VS should be vS
11.69 3-kohms should be
3-kohms
13.33 RS = 1 kohms
and R4 = 1 kohms
14.1 In Fig.
14.1(m), the power supply should be positive: +VDD.
14.14 VCC = 15 V,
-VEE = -15 V
14.69 C3 = 2.2 uF.
14.76 Ignore reference to C3.
14.115 C3 = 2.2 uF
14.122 C1 = C2 =C3 = 1 uF.
15.96 Ignore the last
sentence in the problem statement.
15.203 Problem should refer to Prob.
15.202.
16.57 This problem is a
follow-on to Ex. 16.6 on page 1021 which uses current gain = 100 and infinite
Early voltage.
16.58 VCC = +12 V.
16.65 Problem should refer to
Prob. 16.14(e).
16.83 RL is
connected between the collectors of transistors Q1 and Q2.
17.104 The transistor parameters should be
Kp = 1.25 mA/V2 and VTN = -4 V.
17.108 RS = 820 ohms, and the
transistor parameters should be Kp = 1.25 mA/V2 and VTN
= -4 V.
